F(\Xd7)=\Xd7+1andg(\Xd7)=2\Xd7-2find(F-G)(\Xd7)

F(×)=×+1andg(×)=2×-2find(f-g)(×)

 

"f(x) = x + 1, g(x) = 2x - 2, find (f - g)(x)"

(f - g)(x) = f(x) - g(x)

(f - g)(x) = (x + 1) - (2x - 2)

(f - g)(x) = x + 1 - 2x + 2

(f - g)(x) = -x + 3 or (f - g)(x) = 3 - x


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